updated the formating for AMS_T and temp-sens-dist

temperature-measurement-error/AMS_T_error.tex

@@ -8,7 +8,7 @@
      group-separator = {.},
      input-decimal-markers={.},
 %     output-decimal-marker = {,},
-     group-minimum-digits=4}
+     group-minimum-digits=9}
 \usepackage{graphicx}
 \usepackage{fancyhdr}
 \usepackage{lastpage}
@@ -20,7 +20,7 @@
 \pagestyle{fancy}
 \fancyhf{}
 
-\rhead{\includegraphics*[scale=0.03]{bilder/Fasttube-Logo.png}}
+\rhead{\includegraphics*[scale=0.01]{./bilder/FaSTTUBe_Logo_ohneAuto.png}}
 \rfoot{Page \thepage \hspace{1pt} of \pageref{LastPage}}
 
 \begin{document}
@@ -28,8 +28,6 @@
 \lhead{Car 313, 06.03.2025, Rev. 1}
 \chead{\large Temperature Measurement Error Calculation}
 
-\hfill \break
-
 Since the Look Up Table provided by Vishay is used for the calculation in the AMS Software, the following calculation is also based on it.
 
 As the characteristic curve is not linear, it is relatively trivial to find the absolute maximum measurement error, therefore, the maximum error at \SI{60}{\celsius} is calculated here.
@@ -38,19 +36,19 @@ Our Voltage measurement system is based on a NTC (NTCLE413E2103F102L from Vishay
 
 To calculate the error, the highest possible measured voltage at \SI{60}{\celsius} is worked out here, since according to the design of our voltage divider, the lower the temperature, the higher the voltage. As shown in Fig. \ref{fig:vref2}, the supply voltage $V_{REF2}$ of the voltage divider can have a maximum value of \SI{3.006}{\volt}, while the total measurement error of the GPIO is $\pm$ \SI{2.8}{mV}. (Fig. \ref{fig:aux}) In addition, the maximum resistance from the NTC can be \SI{3086.8}{\ohm} according to the LUT (Tab. \ref{tab:lut}). the maximum possible voltage recorded is therefore:
 
-\begin{align*}
+\begin{align}
-	        & V_{REF2} \cdot \frac{R_{NTC}}{R_{NTC}+R_1} + V_{err} \\
+	V_{worstcase} &= V_{REF2} \cdot \frac{R_{NTC}}{R_{NTC}+R_1} + V_{err}  \\
-	=       & 3.006V \cdot \frac{3086.8}{3086.8+9990} + 0.0028V    \\
+	&= \SI{3.006}{\volt} \cdot \frac{3086.8}{3086.8+9990} + 0.0028V \\
-	\approx & 712.4V
+	&\approx 712.4mV
-\end{align*}
+\end{align}
 
 to find the largest possible error, the lowest possible matching temperature should be calculated, that theoretically can produce the same voltage output. The calculation is as below:
 
-\begin{align*}
+\begin{align}
-	  & V_{REF2} \cdot \frac{R_{NTC}}{R_{NTC}+R_1} + V_{err}          \\
+	V_{worstcase} &= V_{REF2} \cdot \frac{R_{NTC}}{R_{NTC}+R_1} + V_{err}  \\
-	= & 2.994V \cdot \frac{R_{NTC}}{R_{NTC}+10010} - 0.0028V = 712.4V \\
+	712.4V &= 2.994V \cdot \frac{R_{NTC}}{R_{NTC}+10010} - 0.0028V \\
-	  & R_{NTC} \approx 3141.6
+	R_{NTC} &\approx 3141.6
-\end{align*}
+\end{align}
 
 since the LUT is used to match the voltage to the temperature, and the nominal resistance from the LUT is used for the calculation, the closest matching temperature is \SI{58.7}{\celsius}.
 

temperature-sensor-distibution/temp-sens-dist.tex

@@ -20,7 +20,7 @@
 \pagestyle{fancy}
 \fancyhf{}
 
-\rhead{\includegraphics*[scale=0.012]{./Pictures/FaSTTUBe_Logo_ohneAuto.png}}
+\rhead{\includegraphics*[scale=0.01]{./Pictures/FaSTTUBe_Logo_ohneAuto.png}}
 
 \begin{document}
 
@@ -29,14 +29,14 @@
 
 \begin{figure}[H]
 	\centering
-	\includegraphics[width=\textwidth]{./Pictures/iButton-Accumulator.png}
+	\includegraphics[scale=0.8]{./Pictures/iButton-Accumulator.png}
 	\caption{iButton Accumulator View}
 	\label{fig:accu-view}
 \end{figure}
 
 \begin{figure}[H]
 	\centering
-	\includegraphics[width=\textwidth]{./Pictures/iButton-Stack.png}
+	\includegraphics[scale=1.2]{./Pictures/iButton-Stack.png}
 	\caption{iButton Accumulator View}
 	\label{fig:stack-view}
 \end{figure}