printf: handle unsigned modifier for long long
Otherwise, an unsigned integer will be displayed as a signed one if we use internal print, ie HAVE_LONG_LONG_FORMAT is not defined. https://bugzilla.gnome.org/show_bug.cgi?id=746096
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@ -121,6 +121,11 @@ print_long_long (char *buf,
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digits = upper;
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negative = FALSE;
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break;
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case 'u':
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base = 10;
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digits = lower;
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negative = FALSE;
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break;
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default:
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base = 10;
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digits = lower;
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